Integrand size = 28, antiderivative size = 109 \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\frac {i 2^{\frac {7+m}{2}} a^3 \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (-5-m),\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{\frac {1}{2} (-1-m)} \sqrt {a+i a \tan (c+d x)}}{d m} \]
[Out]
Time = 0.24 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3586, 3604, 72, 71} \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\frac {i a^3 2^{\frac {m+7}{2}} \sqrt {a+i a \tan (c+d x)} (1+i \tan (c+d x))^{\frac {1}{2} (-m-1)} (e \sec (c+d x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (-m-5),\frac {m}{2},\frac {m+2}{2},\frac {1}{2} (1-i \tan (c+d x))\right )}{d m} \]
[In]
[Out]
Rule 71
Rule 72
Rule 3586
Rule 3604
Rubi steps \begin{align*} \text {integral}& = \left ((e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \int (a-i a \tan (c+d x))^{m/2} (a+i a \tan (c+d x))^{\frac {7}{2}+\frac {m}{2}} \, dx \\ & = \frac {\left (a^2 (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \text {Subst}\left (\int (a-i a x)^{-1+\frac {m}{2}} (a+i a x)^{\frac {5}{2}+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {\left (2^{\frac {5}{2}+\frac {m}{2}} a^4 (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} \sqrt {a+i a \tan (c+d x)} \left (\frac {a+i a \tan (c+d x)}{a}\right )^{-\frac {1}{2}-\frac {m}{2}}\right ) \text {Subst}\left (\int \left (\frac {1}{2}+\frac {i x}{2}\right )^{\frac {5}{2}+\frac {m}{2}} (a-i a x)^{-1+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {i 2^{\frac {7+m}{2}} a^3 \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (-5-m),\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{\frac {1}{2} (-1-m)} \sqrt {a+i a \tan (c+d x)}}{d m} \\ \end{align*}
Time = 3.29 (sec) , antiderivative size = 186, normalized size of antiderivative = 1.71 \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=-\frac {i 2^{\frac {7}{2}+m} e^{3 i (c+2 d x)} \sqrt {e^{i d x}} \left (\frac {e^{i (c+d x)}}{1+e^{2 i (c+d x)}}\right )^{\frac {1}{2}+m} \left (1+e^{2 i (c+d x)}\right )^{\frac {1}{2}+m} \operatorname {Hypergeometric2F1}\left (\frac {7}{2}+m,\frac {7+m}{2},\frac {9+m}{2},-e^{2 i (c+d x)}\right ) \sec ^{-\frac {7}{2}-m}(c+d x) (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2}}{d (7+m) (\cos (d x)+i \sin (d x))^{7/2}} \]
[In]
[Out]
\[\int \left (e \sec \left (d x +c \right )\right )^{m} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {7}{2}}d x\]
[In]
[Out]
\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {7}{2}} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {7}{2}} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {7}{2}} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^{7/2} \, dx=\int {\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^m\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{7/2} \,d x \]
[In]
[Out]